NEED HELP ASAP
algebra 2

x = sqrt(17)

Step-by-step explanation:

Since this is a right triangle we can use the Pythagorean theorem

a^2 + b^2 = c^2

Let the unknown side be x

8^2 + x^2 = 9^2

64 + x^2 = 81

Subtract 64 from each side

x^2 = 81-64

x^2 =17

Taking the square root of each side

x = sqrt(17)

x = √17

Step-by-step explanation:

Your question have a right triangle.

So, we could use the Pythagorean Theorem.

Pythagorean Theorem is a² + b² = c².

So, 8² + n² = 9².

8² is 64, and 9² is 81.

So, 'n' is 81 - 64.

Let's see... 81 - 64 is 17.

So, It is √17.

Because when you use the Pythagorean Theorem, it is 8² + (√17)² = 9².

Otherwise, 64 +  (√17)² = 81.

And, √17 is 4.12 when rounding to a hundredth.

Hope it helps!

Bye!

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a

answer: idk wbu

step-by-step explanation: