flying against the wind, a jet travels 4600 miles in 5 hours. flying with the wind, the same jet travels 4200 miles in 3 hours. what is the rate of the jet in still air and what is the rate of the wind?

The rate of the jet in still wind is 1160 MPH and the rate of the wind is 240 MPH.

Step-by-step explanation:

Distance equals rate times time (d = rt)

Against the wind, the rate is:

4600 = r * 5

r = 4600/5 = 920 MPH

With the wind, the rate is:

4200 = r * 3

r = 4200/3 = 1400 MPH

Let W be the rate of the wind in MPH. We know that:

(rate of the jet against the wind) + (rate of the wind) = (rate of the jet with the wind ) - (rate of the wind), so:

920 + W = 1400 - W

2W = 480

W = 240 MPH

And the speed of the jet in still air would be:

1400 - 240 = 1160 MPH

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.

the 3rd option is right

step-by-step explanation: