If AB ll CD , EF ll BC, angle bac = 65 and angle dhf = 35 find angle agh

100

Step-by-step explanation:

You know that AB is || to CD, angle BAC ≅ ACD  (this is the theorem where a line connecting the diagnose of two parallel line, the alternative interior angles are equal/ congruent)

You know that EF is || to BC, angle DHF ≅ GHC (these two are  vertically opposite angle which are equal/ this is a theorem)

we now know the angles in ΔGHC where angle GHC=35, angle GCH=65, and angle CGH=80 (subtract other angles from 180)

angle AGH is supplementary w=angle with CGH, which means we subtract 80 from 180, we get 100 will be the angle of AGH

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

your answer is 228

step-by-step explanation:

add the top and bottom bases together, then divide them by 2, then multiply by the height.