A suitcase has a lock on it consisting of four numbers. Each number could be any number 0-9. The only restriction is that the last slot has to be an even number.

We have 5000 possible combinations.

Step-by-step explanation:

I guess that we want to find the possible combinations for this lock.

We have 4 numbers, so we have 4 selections.

Now, let's count the number of options in each selection.

in the first selection, we have 10 options (0, 1, 2, 3, 4, 5, 6, 7, 8 and 9)

in the second selection, we have 10 options (0, 1, 2, 3, 4, 5, 6, 7, 8 and 9)

in the third selection, we have 10 options (0, 1, 2, 3, 4, 5, 6, 7, 8 and 9)

in the last selection, we have 5 options (0, 2, 4, 6 and 8)

The total number of combinations is equal to the product of the number of options in each selection:

C = 10*10*10*5 = 5000 combinations.