The solutions to the equation 2x^2+x-1=2 are x=-3/2 or x= blank

Step-by-step explanation:

hello :

2x²+x-1=2  means : 2x²+x-3=0

a=2  b= 1  c= -3

the solutios are :   x1 and x2 when the product is : x1×x2 = c/a  

let x1 = -3/2  you have : (-3/2)×x2 = -3/2   so x2 = (-3/2)/(-3/2) = 1  

The solutions to the equation 2x²+x-1=2 are x=-3/2 or x= 1

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

answer: h

step-by-step explanation: