Simplify the radical. 2/√6 A)√12/6 B)√3/3 C)√6/3 D)√2

This is the square root of 6 over 3. The 3 is not inside the square root.

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Explanation:

sqrt = square root

We have sqrt(6) in the denominator. Your teacher wants you to rationalize the denominator, which means to take out the square root and instead have an integer here.

To achieve this, we multiply top and bottom of the fraction by sqrt(6) like so

Therefore,

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f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

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