For the points given below, find (a) PQ and (b) the coordinates of the midpoint of PQ. P(0,-3), Q(7,0)

Step-by-step explanation:

Given  P(0,-3), Q(7,0), to get PQ, we will use the formula fr calculating the distance between two points expressed as;

PQ = √(x₂-x₁)²+(y₂-y₁)²

From the given coordinates, x₁ = 0, y₁ = -3, x₂ = 7, y₂ = 0

PQ = √(7-0)²+(0-(-3))²

PQ = √7²+3²

PQ = √49+9

PQ = √58

Let the coordinte of the midpoint be (X, Y)

X = x₁+x₂/2 and Y = y₁+y₂/2

Substituting the given coordinates will give;

X = 0+7/2

X = 7/2

X = 3.5

Y = -3+0/2

Y = -3/2

Y = -1.5

Hence, the coordinates of the midpoint of PQ is (3.5, -1.5)

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2

idk the answer but just put a

step-by-step explanation: