A function f(x) has range {yer 1-50}. Explain why reflecting the function vertically would not affect the range

For the reflection property, we have;

For reflection vertically, which is equivalent to reflection across the y-axis, we have;

Let the location or point of the pre-image before, reflection be (x, y), then, the location or point of the image after reflection will be (-x, y)

Therefore, the y-coordinates remains the same

Given that the range of the function is the value of f(x) or y from 1 - 50, which are the y-coordinate values of the function, it will not be affected by the vertical reflection of the function.

Step-by-step explanation:

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew

maybe showing the graph would

step-by-step explanation:

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