Which statement is true about this equation? 3(-y + 7) = 3(y + 5) + 6 A. The equation has one solution, y = 0. B. The equation has one solution, y = -1. C. The equation has no solution. D. The equation has infinitely many solutions.

y=0 So its A

Step-by-step explanation:3(-y+7)=3(y+5)+6

We move all terms to the left:

3(-y+7)-(3(y+5)+6)=0

We add all the numbers together, and all the variables

3(-1y+7)-(3(y+5)+6)=0

We multiply parentheses

-3y-(3(y+5)+6)+21=0

We calculate terms in parentheses: -(3(y+5)+6), so:

3(y+5)+6

We multiply parentheses

3y+15+6

We add all the numbers together, and all the variables

3y+21

Back to the equation:

-(3y+21)

We get rid of parentheses

-3y-3y-21+21=0

We add all the numbers together, and all the variables

-6y=0

y=0/-6

y=0

"if it is my birthday, then it is snowing"

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐