(20pts)prove that the difference of the squares of two consecutive integers is equal to the sum of the integers, whenever the larger of the two integers comes first

see below (I hope this helps!)

Step-by-step explanation:

If the two numbers are x and x + 1, then:

(x + 1)² - x²

= x² + 2x + 1 - x²

= 2x + 1

= x + (x + 1)

answer: a.   one is a factor of every whole number since every number is divisible by itself.

3 is greater then both of those numbers