If a fish experiences an acceleration of 9.8 m/s^2 over a period of 1.4s (It must be falling), then what is its change in velocity?

Change In velocity= 13.72 ms^-1

Step-by-step explanation:

fish experiences an acceleration of

9.8 m/s^2 over a period of 1.4s

Change in velocity/time= acceleration

Time in seconds= 1.4 s

Acceleration in meter per second square= 9.8 m/s^2

Change in velocity/time= acceleration

Change In velocity= acceleration*time

Change In velocity= 9.8*1.4(m/s^2 *s)

Change In velocity= 13.72 ms^-1

your answer would be 10x - 1

i believe the answer is d.

hope it you! : d