Why is f (t) = (3x + 3)? + not the vertex form of f (x) = 9r2 + 2x + 1? (1 point) O The variable x has a coefficient.
O The expression is not the product of two binomials.
O Some of the terms are fractions instead of integers.
O The expression has a constant outside of the squared term.

This makes absolutely no sense at all young man/women

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!

Answer to your question: a. the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. the roots are ​ x=1±i7√2 .number of roots=degree of polynomialhere, degree of polynomial is 2 so number of roots will be 2.hope it *_*