A pool measures 15 feet by 17 feet. A cement walkway is added around the pool, to both the width and the length. The area of the pool and the cement walkway is
now 483 square feet. What is the width of the cement walkway?

The width of the walkway is 3 ft

The pool measures 15 feet by 17 feet. This means the pool is rectangular.

area of the pool = lw

area = 15 × 17 = 255 ft²

A cement walkway is added around the pool, to both the width and the length.

area of the pool and the cement walkway = 483 ft²

Therefore,

area = lw

The width and length was added on both sides.

let

the side added to the width = x

the side added to the length = x

length = 2x + 17

width = 2x + 15

483 = (2x + 17)(2x + 15)

483 = 4x² + 30x + 34x + 255

4x² + 64x - 228 = 0

x² + 16x - 57

x² - 3x + 19x - 57

x(x - 3) + 19(x - 3)

(x + 19)(x - 3) = 0

x = -19 or 3

we can only use positive value of x. Therefore, x = 3

length = 2(3) + 17 = 23 ft

width = 2(3) + 15 = 21 ft

Therefore, the width of the walkway is 21 - 15 / 2 = 3 ft

learn more on rectangle here:link

Width of the walkway = 3 feet

Step-by-step explanation:

Dimensions of a pool = 15 feet × 17 feet

After the addition of a cement walkway around the pool,

New dimensions of the pool (including walkway) = (l + 2x)(w + 2x)

Area of the pool and the cement walkway = 483 square feet

(15 + 2x)(17 + 2x) = 483 [Since, l = 15 feet and w = 17 feet]

255 + 30x + 34x + 4x² = 483

4x² + 64x = 483 - 255

4x² + 64x = 228

4x² + 64x - 228 = 0

x² + 16x - 57 = 0

By using quadratic formula,

x =

x =

x = 3.0 ft, -19 ft

Since, dimension can't be negative.

Therefore, width of the walkway = 3 ft

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation: