What is the positive root of the equation x2 + 5x = 150?
ao

10.

Step-by-step explanation:

x^2 + 5x = 150

x^2 + 5x - 150 = 0

This equation will factor:

(x - 10)(x + 15) = 0

x - 10 = 0 or x + 15 = 0, so:

x = 10 or -15.

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Work Shown:

First get everything to one side

Now use the quadratic formula

Plug in a = 1, b = 5, c = -150.

Factoring, completing the square, or graphing are alternative methods to get these two answers. We see that the positive root is x = 10.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

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