10. In 2005 there were 9 million bicycles in Beijing, correct to the nearest million.
The average distance travelled by each bicycle in one day was
6.5 km correct to one decimal place.
Work out the upper bound for the total distance travelled by all the
bicycles in one day,

Total distance = 6,540,000 km

Step-by-step explanation:

Given

Number of bicycles = 9,000,000

Average Distance = 6.5 km (to 1 d.p)

Required

Calculate the upper bound of all bicycle distance

First, we need to determine the range of the distance traveled by each bicycle;

Since, the average distance is approximated, then the Range is:

All number in this range approximate to 6.5km

Note that the upper bound of the range is 6.54km;

Hence, total distance is calculated as thus;

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3