The vertical position y (in feet) of a rock t seconds after it was dropped from a cliff is given by the formula y equals short dash 16 t squared plus 4 t plus 380. The base of the cliff corresponds to y equals 0. After how many seconds will the rock hit the ground at the base of the cliff?

t = 4.87s

Step-by-step explanation: The vertical position y is given by

If y at the base of the cliff equals 0, then equation is

t = 4.87

Since it is time we want, the negative value of the square root can be ignored. So, at the base of the cliff, the rock will hit the ground after 4.87 seconds.

the answer is 62

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.