A caterpillar is currently valued at 70,35000 if its loses 12% of its value at the beginning of each year, find its value after three and half years, find the depreciation after 3years

4080300-after 3 and half years

=4794155.52-depreciation

Step-by-step explanation:

12%of 70,35000

12/100×70,35000×3.5=

2954700

70,35000-2954700=4080300

D=P(1-12÷100)³

7035000(1-12÷100)³

=4794155.52

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step-by-step explanation:

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step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3