A train starts at Omaha at 2 pm and heads for Reedley, 750 km away. At the same time, a train leaves Reedley and heads for Omaha at 85 km per hour. If the trains meet at 5 pm, what is the rate of the first train

250 km per hour

Step-by-step explanation:

In order to find the rate of the first train, we need to know that the distance between Omaha and Reedly is 750 km away and that it will move at 2 pm and arrive at the location at 5 pm. So, first subtract the hours from 5 to 2.  5 - 2 = 3

The train would arrive in 3 hours.. so we substitute 3 into the number of hours.

Distance = 750

km (kilometers per hour) = ?

Hours = 3

Now we should substitute the number values into the equation, it should look like this:  750 = km(3)

3 multiplied by the varible will be 3km because there is no coefficient for km.

750 = 3km

Then, we divide 3 by both sides to make the 3 into a one for km.

750 ÷ 3 = 3km ÷ 3

250 = km

step-by-step explanation:

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about the problem:

srry i'm not done ! i'll