11. A bus currently has three passengers, Crew, Marty and Blakely. Marty's age is 1.5
times Crew's age. Blakely's age is .75 times
Crew's age. If the sum of the three ages is
104, find the age of each passenger.

Crew :
Marty:
Blakely:

Crew's age is 32, Marty's age is 48 and Blakey's age is 24

Let :

c represent Crew's age

m represent Marty's age

b represent Blakely's age

From the question, the following can be derived

m = 1.5c

b = 0.75c

m + b + c = 104

Substitute for m and b in the above equation

c + 1.5c + 0.75c = 104

3.25c = 104

divide both sides of the above equation by 3.25

c = 104 / 3.25

c = 32

Substitute for c in the equations that represent  Marty and Blakely's age

m = 1.5c

m = 1.5(32)

m = 48

b = 0.75c

0.75(32)

b = 24

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Crew: 32

Marty: 48

Blakely: 24

Step-by-step explanation:

I mainly just used guess and check. Crew is 32 years old. So, let's find Marty's age.

32 × 1. 5 = 48

Marty is 48. Now, let's find Blakely's age.

32 × 0.75 = 24

Add all the ages together.

32 + 48 + 24 = 104

Hope that helps.