Two fair dice are tossed together once. Find the probability that the sum of the outcome is at least 10

p = 1/6.

Step-by-step explanation:

First, we have two fair dice, so we have two events.

The number of outcomes for each dice is 6, then the total number of outcomes for the two dice is equal to the product of the number of outcomes in each event.

C = 6*6 = 36.

Now, the combinations that have a sum larger than 10 are:

4 and 6.

6 and 4

5 and 5

5 and 6

6 and 5

6 and 6.

So we have 6 outcomes where the sum of both numbers is larger than 10.

Now, the probability will be equal to the quotient between the number of outcomes where the sum is larger or equal than 10, and the total number of outcomes:

P = 6/36 = 1/6.

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x