A statistical study reported that a drug was effective with a p-value of .042. a. An effective or ineffective sample may be found about 42 times in 1000 samples. (effective or ineffective)
b. The drug is evidently effective at alpha ? = 0.05. (Yes or No)
c. How would that compare to a drug that had a p-value of .087? (More Effective or Less Effective)

(a) An ineffective sample may be found about 42 times in 1000 samples.

(b) Yes, the drug is evidently effective at alpha = 0.05.

(c) A drug that had a p-value of 0.042 is more effective in comparison to a drug that had a p-value of 0.087.

Step-by-step explanation:

We are given that a statistical study reported that a drug was effective with a p-value of 0.042.

Let the Null Hypothesis, : The drug was ineffective.

Alternate Hypothesis, : The drug was effective.

(a) An ineffective sample may be found about 42 times in 1000 samples.

(b) As we know that, if the P-value is less than the level of significance, then we have sufficient evidence to reject our null hypothesis.

SO, here also; the P-value is less than the level of significance as 0.042 < 0.05, so we reject our null hypothesis and conclude that the drug is evidently effective.

(c) The drug that had a p-value of 0.087 would be ineffective as in this case the P-value is more than the level of significance as 0.087 > 0.05, so we do not reject our null hypothesis and conclude that the drug is evidently ineffective.

This means that a drug that had a p-value of 0.042 is more effective in comparison to a drug that had a p-value of 0.087.

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497

answer: 0.64

step-by-step explanation: