A particle is moving along a projectile path at an initial height of 160 feet with an initial speed of 144 feet per second. This can be represented by the function H(t) = −16t2 + 144t + 160. What is the maximum height of the particle?

The maximum height of the particle is 484 m.

Step-by-step explanation:

Given that,

A particle is moving along a projectile path at an initial height of 160 feet with an initial speed of 144 feet per second. This can be represented by the function :

....(1)

We need to find the maximum height of the particle. For maximum height put

So,

Put t = 4.5 s in equation (1) as :

So, the maximum height of the particle is 484 m.

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step-by-step explanation:

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb