The central angle of sector R is 38° and the central angle of sector Q is 39°. What is the probability that the spinner does not land on Q or R? P Q R S T U

0.786

Step-by-step explanation:

Here i would assume that:

Sector R and Sector Q do not have any sections in common.

Then, the probability that the spinner does not land on Q or R, is equal to the probability where the spinner does not land in a specified section of:

38° + 39° = 77°.

Now, the total section off the spinner is 360°.

If we remove those 77°, we have a section of:

360° - 77° = 283°

So we have 283° where the spinner CAN land on.

Then the probability that the spinner does NOT land on R or Q is equal to the quotient between the section of the spinner that is not R or Q, and the total section of the spinner"

P = 283/360 = 0.786

So the probability is 0.786

answer: the answer to your question is parallel