Ifcosa3/5find the sina

tan∠A = BC/AC = 4/3

sin∠A = BC/AB = 4/5

Actually I found tan too...

Picture a right triangle with the right angle being ∠C. Label the other two angles ∠A and ∠B.

cos is defined to be the ratio of the adjacent side to the hypotenuse.

In this triangle, AB is the hypotenuse, side AC is the side adjacent to ∠A and side BC is the side opposite to ∠A.

cos∠A = 3/5 = AC/AB

Since this is a right triangle, use the Pythagorean Theorem to find the value of the third side:

AC² + BC² = AB² ---> 3² + BC² = 5² ---> BC = 4

sin is defined to be the ratio of the opposite side to the hypotenuse.

sin∠A = BC/AB = 4/5

tan is defined to be the ratio of the opposite side to the adjacent side.

tan∠A = BC/AC = 4/3

Hope it helped u if yes mark me BRAINLIEST!

Tysm!

because they could drop even lower..