PLEASE HELPWILL GIVE BRAINLIEST 1/x+7 = 15/5(x+7) - 2 or

Greetings from Brasil...

We will pass the - 2 to the 1st member

2 + [1/(X + 7)] = 15/(5(X + 7))

simplifying the numerator and denominator of the 2nd member

2 + [1/(X + 7)] = 3/(X + 7)

solving the sum of the 1st member

(2X + 15)/(X + 7) = 3/(X + 7)

product of the means by extremes

(2X + 15) · (X + 7) = 3 · (X + 7)

2X² + 15X + 14X + 105 = 3X + 21

2X² + 29X - 3X + 105 - 21 = 0

solving this 2nd degree equation

Δ = b² - 4.a.c

Δ = 26² -  4 . 2 . 84

Δ = 676 - 4. 2 . 84

Δ = 4

X' = (-26 + √4)/2.2    X'' = (-26 - √4)/2.2

X' = -24 / 4    X'' = -28 / 4

123

step-by-step explanation:

agngel

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°