A similar follow-up study is done on a sample of 25 meat-lovers who never eat vegetables, again randomly selected from the same general population (population mean life expectancy = 75, population standard deviation = 5). This new sample of meat-eaters live to an average age of 77. What is the lower limit and upper limit of the 95% confidence interval for the life expectancy of this sample of meat-lovers?

The lower limit is  75.04

The upper  limit is  78.96

Step-by-step explanation:

From the question we are told that

   The sample size is  

   The sample mean is  

    The standard deviation is  

Given that the confidence level is 95%  then the level of significance is mathematically represented as

The critical value for   obtained from the normal distribution table is  

Generally the margin of error is mathematically represented as

=>  

=>    

The 95% confidence interval is mathematically represented as

=>  

=>  

(a) the volume of the cone is 20/3 in3

hence, option a is correct.

54 km / hours

step-by-step explanation:

we need to convert seconds to hours

60 seconds = 1 minutes

60 minutes = 1hour

15 m         60 second   60 minutes

  * *         = 54000 meters/ hour

second     1 minute             1 hour

now we need to convert meters to km

1000 m = 1 km

54000 m       1 km

*   = 54 km / hours

hour               1000m