The length of a rectangle is 6 meters less than twice its width. If the area of the rectangle is 308 m2, what are its dimensions?

Step-by-step explanation:

Area of a rectangle = l × w

where

l is the length

w is the width

From the question

Area = 308 m²

The length of a rectangle is 6 meters less than twice its width is written as

l = 2w - 6

Substitute this into the above formula and solve for the width

We have

308 = (2w - 6)w

2w² - 6w = 308

2w² - 6w - 308 = 0

Divide both sides by 2

We have

w² - 3w - 154 = 0

( w + 11)( w - 14) = 0

w + 11 = 0 w - 14 = 0

w = - 11 w = 14

Since the width cannot be negative

w = 14

Substitute w = 14 into l = 2w - 6

That's

l = 14(2) - 6

l = 28 - 6

l = 22

Therefore

length = 22cm

width = 14cm

Hope this helps you

the aswere is the one with all 8's and the second one is with the 10,8 and 6

step-by-step explanation: