What is the remainder when f(x) = x^2 + 14x − 8 is divided by (x − 5)? 103 88 87 72

The remainder is 87.

Step-by-step explanation:

By definition of remainder theorem, whenever a polynomial f(x) is divided by (x-b) the remainder will be: f(b)

Following the Remainder Theorem, in this question the remainder will be f(5).

In this case we were given f(x) as

f(x) = x^2 + 14x − 8

We're are to find the remainder when it is divided by (x-5)

Then(x-5)= 0

X=5

If we substitute x=5 into equation of f(x), we will have the remainder of

f(x) = x^2 + 14x − 8

f(4)= (5)^2 +14(5)-8

f(4)=25+70-8

f(4)=87

Hence, The remainder is 87.

m a t h w a y. c o m

step-by-step explanation:

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