If AM
2x + 5 & MB = x + 14; sovle for x, then find AB.
M
x=
AB=

hx = f(x) - g(x)

f(x) = -2x + 17

g(x) = -5x - 10

You can substitute/plug in (-2x + 17) into "f(x)" since f(x) = -2x + 17, and you can substitute (-5x - 10) into "g(x)" since g(x) = -5x - 10.

h(x) = f(x) - g(x)

h(x) = (-2x + 17) - (-5x - 10)      Now simplify, first distribute -1 into (-5x - 10)

h(x) = (-2x + 17) - (-1)5x - (-1)10  (two negative signs cancel each other out and become positive)

h(x) = -2x + 17 + 5x + 10   Combine like terms (terms that have the same variable and power/exponent)

h(x) = 3x + 27

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation:

translate k to n and reflect across the line containing jk.