A country has a 7 digit phone number system of the form ABC-DEFG. The first digit 'A' can be any number except O or 1. The next 2 digits , B' and 'C, can be any digit , except they cannot repeat . The last 4 digits can be any single digit number 0-9 . How many unique phone numbers are possible?

7,200,000

Step-by-step explanation:

Number of Possibilities for

A) First Digit

There are 10 digits (0, 1, 2, 3, 4, 5, 6, 7, 8, and 9) of which 0 and 1 is not allowed.

Hence there are 8 possibilities for the first digit

B) Second digit

There are 10 posibilities

C) Third digit

Since it mustn't be the same as Second digit

There are 9 possibilities

D) Forth digit

There are 10 possibilities

E) Fifth digit

There are 10 possibilities

F) Sixth digit

There are 10 possibilities

E) Seventh digit

There are 10 possbilities

Total possible ways for the 7-digit phone number is...

8×10×9×10×10×10×10

=7,200,000 possible phone numbers

answer

a the answer hopes this

step-by-step explanation:

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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