Solve. 2x−y+3z=6 2x+y=3 2y−4z=−4 Enter your answer, in the form (x, y,z), in the boxes in simplest terms. x= y= z=

(3/2, 0, 1)

Step-by-step explanation:

From 2x+y=3 we have => y=3-2x

From 2y-4z=-4 we have -4z=-2y-4 => z=1/2y+1 => z=1/2 (3-2x) +1 => z=5/2-x

Plug in y & z to find x

2x−y+3z=6 => 2x+(3-2x)+3(5/2-x)=6 => 2x+3-2x+15/2-3x=6 => 21/2-3x =6 => x=3/2

plug in x to find y

2x+y=3 => 2(1.5) + y =3 => y=0

plug in y to find z

2y -4z =-4 => 2(0)-4z=-4 => -4z=-4 => z=1

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~