HELP WILL GIVE 40 POINTS AND BRAINLIEST Solve these two (second-degree) quadratic equations by factoring. &

Step-by-step explanation:

First equation:  2x^2 + 6x = 0 factors into 2x(x + 3) = 0, so either x = 0 or x = -3.

Second equation:  x^2 + 9x + 14 = 0 factors into (x + 2)(x + 7) = 0.  Thus, either x = -2 or x = -7

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|First we factor out x

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To find equation solutions, solve and

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|To solve the equation, factor using formula To find and , set up a system to be solved.

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Since is positive, and have the same sign. Since is positive, and are both positive. List all such integer pairs that give product 14.

1, 14

2, 7

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Calculate the sum for each pair.

1 + 14 = 15

2 + 7 = 9

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The solution is the pair that gives sum 9.

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Rewrite factored expression using the obtained values.

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To find equation solutions, solve and .

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,xzgv

step-by-step explanation:

; oqirjg'

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58