If m∠OZQ = 125 and m∠OZP = 62, what is m∠PZQ

Step-by-step explanation:

You didn't specify where the point P is so there are two posibilites:

1.

P₁Z is dividing angle OZQ

then:

      m∠P₁ZQ = m∠OZQ - m∠OZP₁ = 125° - 62° = 63°

2.

P₂Z is outside angle OZQ

then

    m∠P₂ZQ = 360° - (m∠OZQ + m∠OZP₂) = 360° - (125° + 62°) = 173°

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

yes. we do proportions in probabilities.