At a certain hospital, the probability of a child being born female is 0.51. If 80 babies are born on the a certain day, the probability that more than half of these babies are female is closest to? a. 0.61, b. 0.70, c. 0.39, d. 0.47, 0.53 (I will award you the brainiest)

Answer :

0.53

Step-by-step explanation:

Given the following :

Probability of female = probability of success on a single trial = 0.51

Number of babies = 80

Probability that more than half of the babies are female : p(X >80/2) = P(X > 40)

The problem can be solved using the binomial probability function :

P(X > 40) = [ p(X= 41) + p(X= 42) + +p(X= 80)]

In other to save computation time, we can use the binomial probability calculator

Hence ; P(X > 40) = 0.527 = 0.53

answer: 1, 3 and 5 are correct

step-by-step explanation:

idk

step-by-step explanation: i just don't