Look at the image. Point F, point B, and point C are linears.
|AD|= |FB|= |BC| , [FD] is a perpendicular of [AC] .
Angle DFC= 12°

find the value of angle BAC= x
(with detail please)

ans:39

Tap on the photo

first prove triangle BHC similar to FDC.Reason(AA)

then,provrSBH and GBH congruent(SAS)

CB=CG

CBG is an isolesis triangle

angle G and CBG is X

angle BCG=180-90-12=180-78=102

X=(108-102)/2=39

12m

step-by-step explanation:

square root means have of a number so have of 3 is 1.5 then multiply it by 8 and you get your answer!