What is the center of a circle with the equation (x - 6)2 + (y + 2)2 = 9? A)
(6,2)
B)
(6,-2)
0)
(-6, 2)
D)
(-6, -2)

B. (6,-2)

Step-by-step explanation:

The equation of a circle is (x-h)^2+(y-k)^2=r^2

The center of the circle is (h,k)

So, in this problem, h is 6 and k is -2, so the center of this circle is (6,-2).

bull

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3