Only 40% of the students in a certain liberal arts college are males. Question 10 of 11 If two students from this college are selected at random, what is the probability that they are both males

0.16

Step-by-step explanation:

Given;

40% males.

If two students are selected at random, probability (P) that they are both males is given as follows;

P = P(1) x P(2)

Where;

P(1) = Probability that the first one is a male

P(2) = Probability that the second one is also a male

Remember that there are 40% males.

This means that 40 out of 100 students selected is going to be a male.

Therefore, for the first selection, any of the 40 students could be selected. The probability P(1), that the first one is male is therefore;

40 / 100 = 0.4

Also,

Assuming there is replacement, for the second selection, any of the 40 students could be selected. The probability P(2), that the second one is also male is therefore;

40 / 100 = 0.4

Now, from;

P = P(1) x P(2)

P = 0.4 x 0.4

P = 0.16

The probability that they are both males is therefore 0.16

step-by-step explanation:

idk

step-by-step explanation:

i don't know