Which graph could represent a constant balance in a bank account over time? A graph titled Daily Balance. The horizontal axis shows time (days), numbered 1 to 8, and the vertical axis shows Balance (dollars) numbered 5 to 40. The line begins at 35 dollars in 0 days and ends at 0 dollars in 7 days. A graph titled Daily Balance. The horizontal axis shows time (days), numbered 1 to 8, and the vertical axis shows Balance (dollars) numbered 5 to 40. The line begins at 0 dollars in 5 days and extends vertically to 40 dollars in 5 days. A graph titled Daily Balance. The horizontal axis shows time (days), numbered 1 to 8, and the vertical axis shows Balance (dollars) numbered 5 to 40. The line begins at 30 dollars in 0 days and ends at 30 dollars in 8 days. A graph titled Daily Balance. The horizontal axis shows time (days), numbered 1 to 8, and the vertical axis shows Balance (dollars) numbered 5 to 40. The line begins at 0 dollars in 0 days and ends at 40 dollars in 8 days.

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.