Solve for kkk. \dfrac{k}4+ 3= 14 4 k +3=14

k=1

Step-by-step explanation:

Simplify   1/k

    3     2         1

 (((—+2)-(—•k))-4)-(—-2)  = 0

    k     k         k

2.1   Subtracting a whole from a fraction

      2     2 • k

   2 =  —  =  —————

        1       k  

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

1 - (2 • k)     1 - 2k

———————————  =  ——————

     k            k  

Simplify  2/k

 3     2        (1-2k)

 (((—+2)-(—•k))-4)-——————  = 0

    k     k          k  

Simplify 3/k

  3     2        (1-2k)

 (((—+2)-(—•k))-4)-——————  = 0

    k     k          k  

5.1   Adding a whole to a fraction

 3                      (1 - 2k)

 (((— +  2) -  2) -  4) -  ————————  = 0

    k                         k    

6.1   Subtracting a whole from a fraction

        2     2 • k

   2 =  —  =  —————

        1       k  

7.1   Subtracting a whole from a fraction

3 + 2 • k     2k + 3

—————————  =  ——————

    k           k  

8.1       Adding fractions which have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

        2     2 • k

   2 =  —  =  —————

        1       k  

9.1     Pull out like factors :

  2 - 2k  =   -2 • (k - 1)

10.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -2•(k-1)

 ———————— • k = 0 • k

    k    

Now, on the left hand side, the  k  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -2  •  (k-1)  = 0

Equations which are never true:

10.2      Solve :    -2   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation:

10.3      Solve  :    k-1 = 0

Add  1  to both sides of the equation :

                     k = 1

the answer to this question is yes