Lisa is framing a rectangular painting the length is three more than twice the width she uses 30 inches of framing material what is the length of the painting right and solve the equation

To solve this question:

Doing this, we get that the length of the painting is: 11 inches.

Perimeter of a rectangle:

The perimeter of a polygon is the sum of it's sides.

For a rectangle, as the one given in the picture at the end of this answer, which is of the format of the painting, the perimeter is given by:

Lisa is framing a rectangular painting the length is three more than twice the width.

This means that:

Since we want to solve for the length, we write the width as a function of the length, thus:

She uses 30 inches of framing material

This means that the perimeter is of 30 inches, that is:

Since

Thus, the length of the painting is of 11 inches.

A similar question is found at link

The width is 4 inches

The length is 11 inches

Step-by-step explanation:

Let the width  be x inches

Let the length be (2x+3 )inches

Perimeter= 30 inches

therefore, 2(length +breadth)= perimeter

        =>2(2x+3+x)=30

        =>2(3x+3)=30

         =>6x+6=30

          =>6x=30-6

          =>6x=24

           =>x=24/6

           =>x=4

The width is 4 inches

The length is 11 inches  

24/56=hx^7

step-by-step explanation:

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