An archer hits a bullseye 64% of the time. What is the probability the archer hits the bullseye exactly 4 times during 10 total attempts?
a. 242
b. .365
C..077
d. 168

C. 0.077

Step-by-step explanation:

Use binomial probability.

P = nCr pʳ qⁿ⁻ʳ

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1−p).

n = 10, r = 4, p = 0.64, q = 0.36.

P = ₁₀C₄ (0.64)⁴ (0.36)⁶

P = 210 (0.64)⁴ (0.36)⁶

P = 0.077

  the correct choice is marked

step-by-step explanation:

the first two graphs show multiple turning points. the last graphs matches the description in every detail.

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb