From the given figure 7 ,find the value of x if AB is parallel CF and AE = DE, angle BAE = 38°.

*see the given given in the attachment below

x = 109°

Step-by-step Explanation:

Since AB is parallel to CF, m<BAE = m<AED = 38° (alternate interior angles are congruent)

Since AE = DE, ∆AED is an isosceles ∆.

The two base angles of any given isosceles ∆ are said to be congruent.

This means, m<EAD = m<EDA = ½(180 - m<AED)

m<EDA =

m<EDA =

x + m<EDA = 180° (angle on a straight line)

Value of x = 109°

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

step-by-step explanation:

i think its about 8