The pizza has an area of 78.5 in². What is the minimum width of a placemat that can be placed underneath it so that the pizza does not touch the table? Use 3.14 for pi. someone pls help me

The minimum width of a placemat that can be placed underneath the pizza so that the pizza wouldn't touch the table is; 10 inches

We are told that the pizza has an area of 78.5 in². Thus;

A = 78.5 in²

Now, the pizza is circular in shape and the minimum width of a placemat that can be placed underneath the pizza so that the pizza wouldn't touch the table will be the diameter of the pizza

Thus, area of a circle with diameter d is;

A = πd²/4

Plugging in the relevant values, we have;

78.5 = 3.14d²/4

d² = 78.5 × 4/3.14

d² = 100

d = √100

d = 10 inches.

Read more at; link

The minimum width of the placemat is 10 inches.

Step-by-step explanation:

Let suppose that placemat has a square form, whose width must be at least equal to the diameter of the pizza, so that pizza does not touch the table. Hence, the following relationship is obtained:

Where:

- Width of the placemat, measured in inches.

- Diameter of pizza, measured in inches.

The area of the pizza, measured in square inches, is determined by this formula:

The diameter is cleared afterwards:

If and , then:

The minimum width of the placemat is 10 inches.

13.46

step-by-step explanation:

16.80 x .20 = 13.46

d. 145*2 is 290 than the total angle is 360 then minus 290 then divide by two