For how many games is the total cost of bowling equal for the two bowling establishments? Family bowling game $4, shoes $1. Knight owl bowling game $3.75, shoes $2.

If you play 4 games, the price will be the same in the two establishments.

Step-by-step explanation:

Ok, in Family Bowling we have:

$4 per game, plus $1 per shoes (the shoes are paid only one time).

Then, the price for X games, is:

Pa(X) = $4*X + $1.

In Knight Owl Bowling we have:

$3.75 per game and $2 for the shoes, the price for X games will be:

Pb(X) = $3.75*X + $2.

Now, if we want to pay the same in both establishments, we have:

Pa(X) = Pb(x)

$4*X + $1 = $3.75*X + $2

Now we should solve this for X.

$4*X - $3.75*X = $2 - $1 = $1

($4 - $3.75)*X = $1

$0.25*X = $1

X = $1/$0.25 = 4.

If you play 4 games, the price will be the same in the two establishments.

$15 each

step-by-step explanation:

$45/3 children= $15 each