A new community sports complex is being build in Madison. The perimeter of the rectangular playing field is 466 yards. The length of the field is 7 years less than quadruple the width. What are the dimensions of the playing field?

The dimensions of the field is 185 yards by 48 yards

Step-by-step explanation:

Here, we are interested in calculating the dimensions of the field.

Let the width of the field be x yards

From the question, we are made to know that the length of the field is 7 yards less than quadruple ( 4 times) the width

So mathematically, the length of the field will be ;

(4x -7) yards

The perimeter of the field mathematically is:

2(l + b)

Thus;

2(x + 4x- 7) = 466

2(5x -7) = 466

divide both side by 2

5x - 7 = 466/2

5x - 7 = 233

5x = 233 + 7

5x = 240

x = 240/5

x = 48 yards

Length of field is; 4x -7 = 4(48) -7 = 192 - 7 = 185 yards

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.