The pizza has an area of 78.5 in². What is the minimum width of a placemat that can be placed underneath it so that the pizza does not touch the table? Use 3.14 for pi.

Step-by-step explanation:

This problem bothers on the mensuration of flat shapes, circles and square.

we know that the pizza has a  circular profile

and the place-mat has a square profile.

Step one:

let us solve for the radius of the pizza

Step two:

from inspection we know that the width of the place-mat is same as the diameter of the pizza

hence diameter of pizza

= 2r

=2*5

=10 in

step-by-step explanation:

try remembering the steps

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.