State the amplitude and period of f(t) = -0.3sin t/3

Amplitude is 0.3; period is 6π

Step-by-step explanation:

The amplitude is |-0.3| = 0.3.

The period and frequency are related through

                   2π

period  =  

                     b

where b is the coefficient of the independent variable; here that coefficient is 1/3.

Thus, the period here is found using b = 1/3:

period = 2π/b, or 2π/(1/3), or 6π

answer: kljdcdhjbdlchjad oac apoich a

step-by-step explanation:

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )