19 4/12 + 17 2/11 - 16 6/9 = The answer was actually given to me through a download worksheet but I can't come up with it so I need it totally worked out. My answer comes to 20 -5/33 but the answer should not have a negative numerator in it and the answer given was 19 28/33

19 28/33

Step-by-step explanation:

lets work out the whole number parts first:

= 19 + 17 - 16 = 20.

4/12 + 2/11 - 6/9

= 1/3 + 2/11 - 6/9

Find the LCM of the denominators:

3 = 3

11 = 11

9 = 3*3

- so the LCM is 3*3*11 = 99.

So we have:

33/99 + 18/99 - 66/99

= 51/99 - 66/99

= -15/99

= -5/33

So the answer is  20 - 5/33

= 19 28/33

You just had to subtract 5/33 from 20.

4x and 6y

im not sure though

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v