If the 11th term of a geometric sequence is 32 times larger than the 6th term, then what is the common ratio of the sequence

r = 2

Step-by-step explanation:

nth term of a geometric sequence = .

Where,

a = first term, r = common ratio,

We are given that, the 11th term is 32 times larger than the 6th term of the geometric sequence. Thus:

the 6th term can be expressed as

The 11th term is expressed as

Since the 11th term is 32 times larger than the 6th term, therefore, the following equation can be derived to find the common ratio, r, of the sequence:

, therefore:

Divide both sides by ar⁵

Common ratio = 2

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.

let's fu(!

step-by-step explanation: