Find the equation of a line that is perpendicular to the line -2y+20=8x and passes through the point (7,2).

  8y -2 = 2x

Step-by-step explanation:

The equation of the perpendicular line will have the coefficients of x and y swapped, and one of them negated. The constant can be found by substituting the given point value:

  8y +constant = 2x . . . . coefficients swapped; former y-coefficient negated

  8(2) +constant = 2(7) . . . . . fill in given point values (x, y) = (7, 2)

  constant = 14 -16 = -2 . . . . subtract 16

The equation can be written as ...

  8y -2 = 2x

_____

Additional comment

Personally, I prefer standard form, which has common factors removed from the coefficients, and has the constant separated from the variable terms:

  x -4y = -1

Some like the slope-intercept form better:

  y = 1/4x +1/4

Apparently, your curriculum author doesn't care how the equation of the line is written, so we have answered with the same form that was given.

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.